(x^2-3)^2+x^2-3=2

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Solution for (x^2-3)^2+x^2-3=2 equation: 



(x^2-3)^2+x^2-3=2

We move all terms to the left:

(x^2-3)^2+x^2-3-(2)=0

We add all the numbers together, and all the variables

x^2+(x^2-3)^2-5=0

We move all terms containing x to the left, all other terms to the right

x^2+(x^2-3)^2=5

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